lab report

The integrity of conversation of heat energy Objective: To sum calefactive and dusty liquid together and predict the temperature of the pastiche. Equipment/Materials: Styrofoam transfuse, agglomerated scale, Procedures: 1.Take a dry Styrofoam instill mass the loving cup and record. 2.Pour about(predicate) 50 mL to 60 mL mothy piddle away in the cup. commode the cup + bleak H2 O. Record. 3.Take the temperature of arctic H2 O and record. 4.Take about 90 mL to 100 mL of blistering water system. 5.Record the temperature of hot H2 O. 6.Mix the hot water with cold water. Stir restfully and take the temp of the form. 7.Record the mass of the cup + cold H2 O+ hot H2 O. 8.Clean up work area. information: trade of Styrofoam = 3.9g Temperature of cold water = 21̊C tidy sum of Styrofoam cup + cold water = 52.9g Temperature of hot water = 72̊C mess of Styrofoam cup + cold water + hot water = 142.1g Temperature of the mixt ure = 51̊C Calculations: 1.Calculate the mass of cold water. Mass of cup + cold water mass of Styrofoam 52.9g 3.9g = 3.0g 2.Calculate the mass of hot water. Mass of Styrofoam cup + cold water + hot water - Mass of cup + cold water 142.1g 52.9.9g = 89.2g 3.Calculate the temperature of the mixture by applying the law of converstion of heat and energy: (m ∆T Cp)cold water =(m ∆T Cp)hot water (49.0g)(x-21)̊C (4.184 J/g ̊C) = 89.2g (72-x)̊C (4.184 J/g ̊C) 49.0x 1029 = -89.2x + 6422.4 +89.2x +89.2x 138.

2x 1029 = 0 + 6422.4 + 1029 ! +1029__ 0 7451.4 138.2x= 7451.4 138.2 138.2 X=53.9̊C 4. Find the % error. (Real #) - ( your #) x 100 = % error (Real #) (53.9̊C) - (51̊C) x 100 = 5.3% (53.9̊C) Conclusion: The pct error in this experiment was 5.3%. The reasons for experimental errors are: passionateness disadvantage to the surroundings. ...If you want to get a full essay, browse it on our website: BestEssayCheap.com

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